1 tanx 1 sin2x 1 tanx

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The key here is lớn realise that tanx = sinx/cosx. If we write out the left hand side of the equation in terms of sine and cosine we get: cosx/sinx + sinx/cosx These two fractions can be put over a common denominator of sinxcosx lớn give: (cos2x + sin2x)/sinxcosx If we then use the well-known identity cos2x + sin2x = 1, we see that the above expression is equivalent lớn 1/sinxcosx, which is the expression we were required lớn find.

Answered by Hannah M. • Maths tutor


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